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题目链接: http://codeforces.com/contest/545
A:水
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <queue>
#include <set>
using namespace std;
int n, ans[110],tmp[21000],num;
int p[110][110];
int main()
{
while (cin >> n)
{
set<int> q; q.clear();
num = 0;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
{
scanf("%d", &p[i][j]);
if (p[i][j] == -1)
{
q.insert(i);
q.insert(j);
}
else if (p[i][j] == 0)
{
q.insert(i);
q.insert(j);
}
else if (p[i][j] == 1)
{
tmp[num++] = i;
q.insert(j);
}
else if (p[i][j] == 2)
{
tmp[num++] = j;
q.insert(i);
}
else if (p[i][j] == 3)
{
tmp[num++] = i;
tmp[num++] = j;
}
}
for (int i = 0; i < num; i++)
q.erase(tmp[i]);
set<int> ::iterator it;
cout << q.size() << endl;
for (it = q.begin(); it != q.end(); it++)
cout << *it << " ";
cout << endl;
}
return 0;
}
B: s ,t 字符不同的位置 ,奇数用s 偶数t,其他位置随意。
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <queue>
#include <set>
using namespace std;
char s[100010],t[100010];
int ans[100010];
int main()
{
while (cin >> s >> t)
{
int len = strlen(s);
int tmp = 0;
memset(ans,0,sizeof(ans));
int num = 0;
for (int i = 0; i < len; i++)
{
if (s[i] != t[i])
{
tmp++;
ans[i] = -1;
}
}
if (tmp % 2 == 1)
puts("impossible");
else
{
for (int i = 0; i < len; i++)
{
if (ans[i] == -1)
{
num++;
if (num % 2 == 0) printf("%d", (s[i] - '0'));
else printf("%d", (t[i] - '0'));
}
else printf("%d", (s[i] - '0'));
}
printf("\n");
}
}
return 0;
}
C: 贪心直接搞
代码:
#include <vector>
#include <string>
#include <algorithm>
#include <iostream>
#include <stdio.h>
using namespace std;
const int MAXN=100010;
int n;
int dp[10010];
struct node
{
int x;
int y;
int left,right;
}p[MAXN];
bool cmp(node a,node b)
{
return a.x < b.x;
}
int main()
{
while (cin>>n)
{
for(int i=1;i<=n;i++)
{
cin>>p[i].x>>p[i].y;
p[i].left = p[i].x - p[i].y;
p[i].right = p[i].x + p[i].y;
}
sort(p+1,p+1+n,cmp);
int ans=0;
int pos = -2000000000;
for(int i=1;i<=n;i++)
{
if (p[i].x - p[i].y > pos)
{
pos = p[i].x;
ans++;
}
else if (i == n || p[i].x + p[i].y < p[i+1].x)
{
pos = p[i].x + p[i].y;
ans++;
}
else
pos = p[i].x;
}
cout<<ans<<endl;
}
return 0;
}
D: 排序直接搞 ,不满足条件直接不选。
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <queue>
#include <set>
using namespace std;
int n;
int p[100010];
int main()
{
while (cin >> n)
{
for (int i = 1; i <= n; i++) cin >> p[i];
sort(p + 1, p + 1 + n);
long long tot = p[1];
int ans = 1;
for (int i = 2; i <= n; i++)
{
if (p[i] >= tot)
{
ans++;
tot += p[i];
}
}
printf("%d\n",ans);
}
return 0;
}
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