版权声明:转载请注明出处。 https://blog.csdn.net/u014427196/article/details/40592971

http://acm.hdu.edu.cn/showproblem.php?pid=1166

代码风格更新后:

#include <stdio.h>
#include <iostream>
#include <string>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <algorithm>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <vector>

#define Mid(a,b) ( a+((b-a)>>1))
#define ll(x) (x<<1)
#define rr(x) (x<<1|1)

const int N = 200010;

using namespace std;

int m,n;

int a[N];

struct node
{
    int left;
    int right;
    int sum;
    int mid() { return Mid(left, right); }
};

struct segtree
{
    node tree[N * 4];

    void buildtree(int left,int right,int ind)
    {
        tree[ind].left = left;
        tree[ind].right = right;
        tree[ind].sum = 0;

        if (left == right)
            tree[ind].sum = a[left];
        else
        {
            int mid = tree[ind].mid();

            buildtree(left,mid,ll(ind));
            buildtree(mid+1,right,rr(ind));

            tree[ind].sum = max(tree[ll(ind)].sum , tree[rr(ind)].sum);
        }
    }

    void update(int pos,int ind,int val)
    {
        if (tree[ind].left == tree[ind].right) tree[ind].sum = val;
        else
        {
            int mid = tree[ind].mid();

            if (pos <= mid)
                update(pos,ll(ind),val);
            else
                update(pos,rr(ind),val);

            tree[ind].sum = max(tree[ll(ind)].sum , tree[rr(ind)].sum);
        }
    }

    int query(int st ,int ed,int ind)
    {
        int left = tree[ind].left;
        int right = tree[ind].right;

        if (st <= left && right <= ed)
            return tree[ind].sum;

        else
        {
            int mid = tree[ind].mid();
            int sum1 = 0;
            int sum2 = 0;
            if (st <= mid)
                sum1 = query(st,ed,ll(ind));
            if (ed > mid)
                sum2 = query(st,ed,rr(ind));

            return max(sum1 , sum2);
        }
    }
}seg;

int main()
{
    while (scanf("%d %d",&n,&m)!=EOF)
    {
        for (int i = 1; i <= n; i++)
            scanf("%d",&a[i]);

        seg.buildtree(1,n,1);

        char opr[10];
        int c, d;
        while (m--)
        {
            scanf("%s",opr);
            scanf("%d %d",&c,&d);
            if (opr[0] == 'Q')
            {
                printf("%d\n", seg.query(c, d, 1));
            }
            else if (opr[0] == 'U')
            {
                seg.update(c,1,d);
            }
        }
    }
    return 0;
}

之前

#include<stdio.h>
#include<iostream>
#include<math.h>
#include<stdlib.h>
#include<ctype.h>
#include<algorithm>
#include<vector>
#include<string.h>
#include<queue>
#include<stack>
#include<set>
#include<map>
#include <sstream>
#include <time.h>
#include <utility> 
#include <malloc.h> 

using namespace std;

int max (int a,int b)
{
    if (a>=b)
        return a;
    else 
        return b;
}

struct node
{
    int left ;
    int right;
    int sum;
}b[5001000];

int a[5000100];

void build1(int left ,int right ,int i)//建立二叉树(用于求和)
{
    int mid;
    b[i].left =left;
    b[i].right =right ;
    if (left == right )
    {
        b[i].sum=a[left];
        return ;
    }

    mid = (left + right )/2;
    build1(left ,mid,2*i);
    build1( mid+1,right ,2*i+1);
    b[i].sum=b[i*2].sum+b[i*2+1].sum;
}

void build2(int left , int right , int i)//建立二叉树 (RMQ)
{
    int mid;
    b[i].left=left;
    b[i].right=right;
    if(left==right)
    {
        b[i].sum=a[left];
        return ;
    }

    mid=(left+right)/2;
    build2(left,mid,2*i);
    build2(mid+1,right,2*i+1);
    b[i].sum=max(b[2*i].sum , b[2*i+1].sum);

}

void add (int id,int num,int i)//加(减)节点id值num
{
    if(b[i].left == b[i].right )
    {
        b[i].sum += num;
        return ;
    }
    else 
    {
        b[i].sum=b[i].sum+num;
        if (id<= b[i*2].right )
            add (id,num,i*2);
        else
            add (id,num,i*2+1);
    }
}

int query (int left,int right ,int i)//求和 left to right
{
    int mid;
    if (b[i].right  == right && b[i].left ==left )
    return b[i].sum ;

    mid=(b[i].left +b[i].right )/2;    
    if (right <= mid)
        return query (left ,right,2*i);
    else if (left > mid)
        return query (left ,right,2*i+1);
    else
        return query (left ,mid,2*i)+query (mid+1 ,right,2*i+1);
}

int Query(int left, int right,int i)//求最值
{
    int mid;
    if(b[i].left==left && b[i].right ==right) 
        return b[i].sum;
    mid=(b[i].left+b[i].right)/2;
    if(right<=mid) 
        return Query(left,right,2*i);
    if (left>mid ) 
        return Query(left,right,2*i+1);
    if(left<=mid && mid<right)
        return max(Query(left,mid,2*i) , Query(mid+1,right,2*i+1));
}



void  Update(int id,int value,int i)//更新节点id值为value
{
    if(b[i].left==b[i].right)
    {
        b[i].sum=value;
        return ;
    }


        int mid =(b[i].left+b[i].right)/2;
        if(mid>=id) 
            Update(id,value,2*i);
        if(id>mid) 
            Update(id ,value,2*i+1);
        b[i].sum=max(b[i*2].sum , b[2*i+1].sum);//注意更新的时候不仅更新子节点,还要更新父节点

}


int main()
{
    int  n,m;
    while ( scanf  ("%d%d",&n,&m)!=EOF )
    {
        for (int i=1;i<=n;i++)
            scanf ("%d",&a[i]);

        build2(1,n,1);

        char ss[10];
        int c,d;
        for (int i=0;i<m;i++)
        {
            scanf ("%s",ss);
            scanf ("%d%d",&c,&d);
            if (strcmp (ss,"Q") == 0)
            {
                printf("%d\n",Query (c,d,1));
            }
            else
            {
                Update (c,d,1);
            }
        }
    }
    return 0;
}